Answer:
0.2963 or 29.63%
Step-by-step explanation:
There are two possibilities for a machine breaking down:
1 - Overfilled and broke down (O&B)
2- Not overfilled and broke down (N&B)
The probabilities for each outcome are as follows;
[tex]P(O\&B) = 0.05*0.8\\P(O\&B) = 0.04\\[/tex]
[tex]P(N\&B) = (1-0.05)*0.1\\P(N\&B) = 0.095\\[/tex]
Given that the machine broke down, the probability that it was overfilled is:
[tex]P(O|B) =\frac{P(O\&B)}{P(O\&B)+P(N\&B)}\\P(O|B) =\frac{0.04}{0.04+0.095}\\P(O|B) =0.2963=29.63\%[/tex]
The probability is 0.2963 or 29.63%.