Respuesta :
The theoretical mass of ammonia is 56.6 grams when reaction is begun with 10.00 grams of each reactant.
Explanation:
Data given:
mass of reactants = 10 gram
The reactants are hydrogen and nitrogen gas.
Theoretical mass of ammonia =?
balanced chemical reaction is :
3 [tex]H_{2}[/tex] + [tex]N_{2}[/tex] ⇒ 2 N[tex]H_{3}[/tex]
Atomic mass of hydrogen gas = 2 grams/mole
atomic mass of nitrogen gas = 28 grams/mole
number of moles of each reactant is determined:
number of moles = [tex]\frac{mass}{atomic mass of 1 mole}[/tex]
putting the values for hydrogen gas
number of moles = [tex]\frac{10}{2}[/tex]
number of moles = 5
number of moles of nitrogen gas = [tex]\frac{10}{28}[/tex]
= 0.35 moles
from the balanced equation,
3 moles of hydrogen gas reacted to give 2 moles of ammonia
5 moles of hydrogen will give x moles
[tex]\frac{2}{3}[/tex] = [tex]\frac{x}{5}[/tex]
3x =10
x = 3.33 moles
mass of ammonia produced = number of moles x atomic mass
= 3.33 x 17
= 56.61 grams of ammonia produced from hydrogen
For nitrogen gas,
1 mole nitrogen gas reacted to give 2 moles of ammonia gas
0.35 moles will give x moles
[tex]\frac{2}{1} =\frac{x}{0.35}[/tex]
x = 0.7 moles of ammonia formed
mass = number of moles x atomic mass
= 0.7 x 17
= 11.9 grams
Thus the limiting reagent is hydrogen gas in the reaction.
The mass from limiting reagent is called theoretical yield = 56.61 grams
