Answer:
There are 100 boys and 300 girls in School A and there are 300 boys and 500 girls in School B .
Step-by-step explanation:
The ratio of the boys in school A and the boys in school B is 1:3
Let the ratio be x
No. of boys in School A = x
No. of boys in School B = 3x
We are given that The number of boys in school B is 200 higher than the number of boys in school A.
So,[tex]x+200=3x[/tex]
[tex]200=3x-x[/tex]
[tex]200=2x[/tex]
[tex]\frac{200}{2}=x[/tex]
100=x
So, No. of boys in School A = x = 100
No. of boys in School B = 3x =3(100)=300
We are given that the ratio of the girls in school A and the girls in school B is 3:5.
Let the ratio be y
So, No. of girls in School A = 3y
No. of girls in School B = 5y
So, Total No. of students in School A= No. of boys in school A + No. of girls in school A=100+3y
Total No. of students in School B= No. of boys in school B + No. of girls in school B=300+5y
We are given that The number of pupils in school A is equal to half the number of pupils in school B.
So, [tex]100+3y=\frac{1}{2}(300+5y)[/tex]
[tex]200+6y=300+5y[/tex]
[tex]y=100[/tex]
No. of girls in School A = 3y=3(100)=300
No. of girls in School B = 5y=5(100)=500
Hence there are 100 boys and 300 girls in School A and there are 300 boys and 500 girls in School B .
Answer: 100 boys, 300 girls in School A. 300 boys,500 girls in School B
Step-by-step explanation:
