A publisher of a newsmagazine has found through past experience that 60% of subscribers renew their subscriptions. In a random sample of 100 subscribers, 57 indicated that they planned to renew their subscriptions. What is the p-value associated with the test that the current rate of renewals differs from the rate previously experienced? (Round your answer to four decimal places.)

Respuesta :

Answer:

[tex]z=\frac{0.57 -0.6}{\sqrt{\frac{0.6(1-0.6)}{100}}}=-0.612[/tex]  

[tex]p_v =2*P(z<-0.612)=0.5405[/tex]  

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

X=57 represent the subscribers indicated that they planned to renew their subscriptions

[tex]\hat p=\frac{57}{100}=0.57[/tex] estimated proportion of subscribers indicated that they planned to renew their subscriptions

[tex]p_o=0.6[/tex] is the value that we want to test

[tex]\alpha[/tex] represent the significance level

z would represent the statistic (variable of interest)

[tex]p_v[/tex] represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the current rate of renewals differs from the rate previously experienced, so the system of hypothesis are:  

Null hypothesis:[tex]p=0.6[/tex]  

Alternative hypothesis:[tex]p \neq 0.6[/tex]  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)  

The One-Sample Proportion Test is used to assess whether a population proportion [tex]\hat p[/tex] is significantly different from a hypothesized value [tex]p_o[/tex].

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

[tex]z=\frac{0.57 -0.6}{\sqrt{\frac{0.6(1-0.6)}{100}}}=-0.612[/tex]  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

Since is a bilateral test the p value would be:  

[tex]p_v =2*P(z<-0.612)=0.5405[/tex] Â