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An airplane encountered a head wind during a flight between Joppetown and Jawsburgh which took 5 hours and 30 minutes. The return flight took 5 hours. If the distance from Joppetown to Jawsburgh is 2700 ​miles, find the airspeed of the plane​ (the speed of the plane in still​ air) and the speed of the​ wind, assuming both remain constant.

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temdan2001

Answer: a) 490.91 mph

b) 540 mph

c) speed of the​ wind = 49.1 mph

Step-by-step explanation:

Given that flight between Joppetown and Jawsburgh took 5 hours and 30 minutes.

Time t = 5.5hours

Distance = 2700 miles

Speed = distance/ time

Speed = 2700/5.5

Speed = 490.91 mph

The return flight took 5 hours of the same distance from = 2700 ​miles

Speed = 2700/5 = 540 mph

speed of the​ wind = the difference in the two speed

speed of the​ wind = 450 - 490.91

speed of the​ wind = 49.1 mph

Speed = 540m/s

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