Answer:
Ratio of energy stored in the inductor will be 2.536
Explanation:
We have given two inductance [tex]L_1=3.5\times 10^{-3}H[/tex]
[tex]L_2=1.38\times 10^{-4}H[/tex]
As inductors are connected in series so current will be same in both inductor
Energy stored in inductor is equal to [tex]\frac{1}{2}Li^2[/tex]
[tex]U_1=\frac{1}{2}\times 3.5\times 10^{-3}\times i^2......EQN 1[/tex]
Energy stored in second inductor
[tex]U_2=\frac{1}{2}\times 1.38\times 10^{-4}\times i^2......EQN 2[/tex]
Dividing equation 1 by equation 2
[tex]\frac{U_1}{U_2}=\frac{\frac{1}{2}\times 3.5\times 10^{-3}i^2}{\frac{1}{2}\times 1.38\times 10^{-4}i^2}=2.536[/tex]
