An ant arrives at the snail’s starting position at time t=12 minutes and follows the snail’s path. During the interval 12≤t≤15 minutes, the ant travels in the same direction as the snail with a constant acceleration of 2 inches per minute per minute. The ant catches up to the snail at time t=15 minutes. The ant’s velocity at time t=12 is B inches per minute. Find the value of B.

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Answer:

B=22.348 Inches per minutes

Step-by-step explanation:

A snail is traveling along a straight path. The snail’s velocity can be modeled by [tex]v(t)=1.4ln(1+t^2)[/tex] inches per minute for 0 ≤ t ≤ 15 minutes.

If the snail's velocity is [tex]v(t)=1.4ln(1+t^2)[/tex] per minute, its displacement for 0 ≤ t ≤ 15 minutes is given by the integral:

[tex]\int_{0}^{15}1.4ln(1+t^2)dt=76.04307[/tex]

The ant travels with a constant acceleration of 2 Inches per minute.

Therefore, the velocity of the ant will be:

[tex] \int 2 dt=2t+c,[/tex] inches per minutes, for some constant c.

For the interval, 12≤t≤15, the displacement of the ant is:

[tex] \int_{12}^{15}(2t+c)dt=t^2+ct|_{12}^{15}=81+3c[/tex]

Since the snails displacement and that of the ant are equal in 12≤t≤15.

81+3c=76.04307

3c=76.04307-81

3c=-4.95693

c=-1.65231

The velocity of the ant at t=12 is therefore:

2t+c=2(12)-1.65231=22.348 Inches per minutes

B=22.348 Inches per minutes

The value of B to the nearest whole number, given all of the factors enumerated above, is 22.4 inches/Min. (For the full answer, please see the attached.)

What is velocity?

This simply refers to the pace or rate at which an object or a person changes their position in relation to a frame of reference. It is also a function of time.

See more solutions relating to Velocity at the link below:
https://brainly.com/question/626479

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