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With the two spheres separated by 1 cm you measure the magnitude of the force between the spheres to be LaTeX: F_{12}F 12 . Now you remove the second sphere, and then bring a third identical sphere that is initially uncharged into brief contact with the first sphere before separating them by 1 cm. What is the approximate magnitude of the force between the first and third spheres?

Respuesta :

Answer:[tex]0.25f_{12}[/tex]

Explanation:

Given

When Sphere 1 and 2 are present then force is [tex]f_{12}[/tex]

suppose q is the charge on both the sphere and [tex]d=1\ cm[/tex] is the distance between them then

[tex]f_{12}=\dfrac{kq^2}{d^2}[/tex]

Now sphere 2 is removed and sphere 1 is brought in contact with sphere 3

Charge will be automatically  distributed among two spheres

i.e. both will acquire a charge of [tex]0.5 q[/tex]

Now force between them is

[tex]f'=\dfrac{k\times 0.5q\times 0.5q}{d^2}[/tex]

[tex]f'=0.25\times \dfrac{kq^2}{d^2}[/tex]

[tex]f'=\dfrac{f_{12}}{4}[/tex]

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