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Three elements have the electron configurations 1s22s22p63s1, 1s22s22p63s2, and 1s22s22p5. The first ionization energies of these elements (not in the same order) are 1.681, 0.738, and 0.496 MJ/mol. The atomic radii are 160, 186, and 64 pm. Identify the three elements, and match the appropriate values of ionization energy and atomic radius to each configuration.

Respuesta :

Answer:

Explanation:

1sĀ²2sĀ²2pā¶3sĀ² = magnesium ionization energy, 0.738 MJ/mol atomic radius 160 pm

1sĀ²2sĀ²2pā¶3sĀ¹ = Sodium, ionization energy, 0.496 MJ/mol, atomic radius 186 pm

1sĀ²2sĀ²2pāµ = Florine ionization energy, 1.681 MJ/mol, atomic radius 64 pm

Ionization energy is the minimum amount of energy needed to remove an electron from its orbital around the atom from the influence of the atom while atomic radius is one-half the distance between the nuclei of identical atoms that are bonded together.

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