Answer:
0.5
Step-by-step explanation:
Solution:-
- The sample mean before treatment, μ1 = 46
- The sample mean after treatment, μ2 = 48
- The sample standard deviation σ = √16 = 4
- For the independent samples T-test, Cohen's d is determined by calculating the mean difference between your two groups, and then dividing the result by the pooled standard deviation.
Cohen's d = [tex]\frac{u2 - u1}{sd_p_o_o_l_e_d}[/tex]
- Where, the pooled standard deviation (sd_pooled) is calculated using the formula:
[tex]sd_p_o_o_l_e_d =\sqrt{\frac{SD_1^2 +SD_2^2}{2} }[/tex]
- Assuming that population standard deviation and sample standard deviation are same:
SD_1 = SD_2 = σ = 4
- Then,
[tex]sd_p_o_o_l_e_d =\sqrt{\frac{4^2 +4^2}{2} } = 4[/tex]
- The cohen's d can now be evaliated:
Cohen's d = [tex]\frac{48 - 46}{4} = 0.5[/tex]
