The sum of the measures of the angles of a parallelogram is​ 360°. In the parallelogram on the​ right, angles A and D have the same measure as well as angles C and B. If the measure of angle C is twice the measure of angle​ A, find the measure of each angle.

Respuesta :

Answer:

Measure of [tex]\angle A = \angle D =60[/tex] and [tex]\angle B=\angle C=120[/tex] in degrees.

Step-by-step explanation:

Given:

A parallelogram where angles A and D measures same also, C and B measures same.

According to the question:

Measure of angle C is twice the measure of angle A.

Let the measure of angle A be "x" degree.

Accordingly :

Measure of each angle C and B = "2x"

Measure of each angle A and D ="x"

Note:

The sum of the measures of the angles of a parallelogram is​ 360°.

⇒ [tex]x+x+2x+2x=360[/tex]

⇒ [tex]6x=360[/tex]

⇒ [tex]x=\frac{360}{6}[/tex]

⇒ [tex]x=60[/tex]

So,

Measure of angle A and D be 60 degrees each.

Measure of angle B and C is 120 degrees each.