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18.53 For CaO, the ionic radii for Ca2 and O2 ions are 0.100 and 0.140 nm, respectively. If an externally applied electric field produces a 5% expansion of the lattice, compute the dipole moment for each Ca2O2pair. Assume that this material is completely unpolarized in the absence of an electric field.

Respuesta :

Chrisnando

Answer:

[tex] = 1.92*10^-^3^0 C.m[/tex]

Explanation:

Given:

[tex] r_ca_^2_^+ = 0.100 nm[/tex]

[tex] r_o_^2_^- = 0.14 nm [/tex]

Let's find the distance of separation between cation and anion when there is no applied electric field with the formula:

[tex] d = r_ca_^2_^+ + r_o_^2_^- [/tex]

d = 0.100 nm + 0.140 nm

= 0.240 nm

Let's also calculate the distance of separation between anion and cation when there is an applied electric field.

We use the formula:

∆d = 5%d => 0.05d

= 0.05 * 0.024 nm

∆d = 0.0120 nm

[tex]0.120* 10^-^9m[/tex]

[tex]= 1.20*10^-^1^1m[/tex]

Given magnitude of each dipole= [tex]1.602*10^-^1^9 C [/tex]

Let's find the dipole moment, with the formula:

p = q∆d

Substituting figures in the formula, we have:

[tex]p = 1.602*10^-^1^9 * 12*10^-^2^1 [/tex]

[tex] = 1.92*10^-^3^0 C.m[/tex]

Answer:

Explanation:

Answer:

= 1.92*10^-^3^0 C.m

Explanation:

Given:

r_ca_^2_^+ = 0.100 nm

r_o_^2_^- = 0.14 nm

Let's find the distance of separation between cation and anion when there is no applied electric field with the formula:

d = 0.100 nm + 0.140 nm = 0.240 nm

Let's also calculate the distance of separation between anion and cation when there is an applied electric field.

We use the formula:

∆d = 5%d => 0.05d

= 0.05 * 0.024 nm

∆d = 0.0120 nm

0.120* 10^-^9m

= 1.20*10^-^1^1m

Given magnitude of each dipole= 1.602*10^-^1^9 C

Let's find the dipole moment, with the formula:

p = q∆d

Substituting figures in the formula, we have:

p = 1.602*10^-^1^9 * 12*10^-^2^1

= 1.92*10^-^3^0 C.m

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