Verify that the vector X is a solution of the given system. dx dt = 3x − 5y dy dt = 5x − 7y; X = 1 1 e−2t Writing the system in the form X' = AX for some coefficient matrix A, one obtains the following. X' = X For X = 1 1 e−2t, one has X' = AX = . Since the above expressions , X = 1 1 e−2t is a solution of the given system.

Respuesta :

Answer:

X is a solution of the system.

Step-by-step explanation:

To verify that the vector X is a solution of the given system:

[tex]\frac{dx}{dt}=3x-5y \\\frac{dy}{dt}=5x-7y\\X=\left(\begin{array}{c}1&1\end{array}\right)e^{-2t}[/tex]

Writing the system in the form X'=AX for some coefficient matrix A, one obtains the following.

[tex]X'=\left(\begin{array}{cc}3&-5\\5&-7\end{array}\right)X[/tex]

[tex]For\:X=\left(\begin{array}{c}1&1\end{array}\right)e^{-2t} , X'=\left(\begin{array}{c}-2&-2\end{array}\right)e^{-2t}[/tex]

Similarly:

[tex]AX=\left(\begin{array}{cc}3&-5\\5&-7\end{array}\right)\left(\begin{array}{c}1&1\end{array}\right)e^{-2t}=\left(\begin{array}{c}-2&-2\end{array}\right)e^{-2t}[/tex]

Since the above expressions are equal, [tex]X=\left(\begin{array}{c}1&1\end{array}\right)e^{-2t}[/tex] is a solution of the given system.