Answer:
the second wave will be heard at [tex]2*10^{-3} \ sec[/tex] after the first sound wave.
Explanation:
Given that:
two speakers are placed 500 meters away from each other and a person is standing in the middle;
that implies that the distance of the speed of the wave travelling  is divided into two equal which is 250 m
Now; from the first speaker, time to reach sound wave is;
[tex]t_1 = \frac{250}{v_1}[/tex]
[tex]t_1 = \frac{250}{343}[/tex]
[tex]t_1 = 0.728 \ sec[/tex]
Also from the second speaker; time to reach sound wave is;
[tex]t_2 = \frac{250}{v_2}[/tex]
[tex]t_2 = \frac{250}{342}[/tex]
[tex]t_2 =0.730 \ sec[/tex]
[tex]t_2 - t_1 = (0.730 - 0.728 )\ sec[/tex]
[tex]= 0 .002 \ sec\\\\= 2*10^{-3} \ sec[/tex]
Thus, the second wave will be heard at [tex]2*10^{-3} \ sec[/tex] after the first sound wave.
