Respuesta :
Complete Question:
Spam: A researcher reported that 71.8% of all email sent in a recent month was spam. A system manager at a large corporation believes that the percentage at his company may be 69%. He examines a random sample of 500 emails received at an email server, and finds that 365 of the messages are spam. Can you conclude that greater than 69% of emails are spam? Use both a=0.01 and a=0.05 levels of significance and the -value method with the table.
(a) State the appropriate null and alternate hypotheses.
(b) Compute the -value.
(c) At the a=0.01, can you conclude that greater than 69% of emails are spam?
(d) At the a=0.05, can you conclude that greater than 69% of emails are spam?
Answer and step-by-step explanation:
a)
The required hypothesis are
H₀: [tex]\mu[/tex] = 0.69
H₁: [tex]\mu[/tex] > 0.69
additional solutions are attached in the image below

Answer:
a) No
B) Yes
Step-by-step explanation:
Calculating the p-value, we have;
z = (p-bar) -p/√(p(1-p)/n)
But p-bar = 365/500
= 0.73
Therefore,
z = 0.73 -0.69/√0.69(1-0.69)/500
= 0.04/√0.2139/500
= 0.04/√0.0004278
= 0.04/0.02068
= 1.93
p-value = p(z ≥1.93) = 0.0268
(a) Can you conclude that the percentage of emails that are spam is greater than 69% ?
No, because the p- value is greater than α. That is p-value⊃ 0.01
(b) Can you conclude that the percentage of emails that are spam is greater than 69%
Yes, since p-value ∠ 0.05