Respuesta :

Answer:

Step-by-step explanation:

XY=ST/2

3z+2=(7z-1)/2

2*(3z+2)=7z-1

2*3z+2*2=7z-1

6z+4=7z-1

+1         +1

6z+5=7z

-6z      -6z

5=z

The required value of z is 5.

Given that,

In RST, X is the midpoint of RS,

And Y is the midpoint of RT.

XY = 3z + 2 and ST = 7z - 1.

We have to determine,

What is the value of z.

According to the question,

X is the midpoint of RS,

And Y is the midpoint of RT.

Therefore,

[tex]XY = \frac{ST}{2}[/tex]

Putting the value of XY and ST in the equation,

XY = 3z + 2 and ST = 7z - 1.

Then,

[tex]XY = \frac{RS}{2} \\\\3z+ 2 = \frac{7z-1}{2}\\\\2 \times(3z+2) = 7z-1\\\\= 6z+4= 7z-1\\\\6z-7z = -1-4\\\\-z = -5\\\\= z = 5[/tex]

Hence, The required value of z is 5.

For more information about System of equation click the link given below.

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