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Joey read in his biology book that fish activity increases with water temperature, and he decided to investigate this issue by conducting an experiment. On nine successive days, he measured fish activity and water temperature in his aquarium. He found the equation of the LSRL to be y t ˆ = + 152.1 37.65 , where yˆ is the predicted amount of activity. If one of Joey’s days had a water temperature of 69.0 degrees Fahrenheit and the fish activity on that day was 265, what is the residual activity for this particular temperature?

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Answer:

Step-by-step explanation:

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The residual value is the difference between the actual and predicted values. Hence, the residual activity at a temperature of 69°F will be −2484.95

The equation of the Least Square Regression Line is given as :

  • y = 152.1 + 37.65t

The predicted amount of activity, y at a temperature of 69°F will be :

y = 152.1 + 37.65(69)

y = 2749.95

The actual amount of activity at a temperature of 69°F is 265

The residual activity at 69°F temperature can be calculated thus :

Residual = Actual - Predicted

Residual = 265 - 2749.95 = −2484.95

Therefore, the residual activity at 69°F is −2484.95

Learn more : https://brainly.com/question/18405415

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