contestada

A solution is prepared by dissolving 15.0 g of NH3 in 250 g of water. The density of the resulting solution is 0.974 g/mL. The mole fraction of NH3 in the solution is _____.A) 16.8B) 0.940C) 0.0597D) 0.922E) 0.0640

Respuesta :

Answer:

Mole fraction of [tex]NH_{3}[/tex] in solution is 0.0597.

Explanation:

Molar mass of [tex]NH_{3}[/tex] = 17.031 g/mol

Molar mass of [tex]H_{2}O[/tex] = 18.015 g/mol

No. of moles = (mass)/(molar mass)

So, 15.0 g of [tex]NH_{3}[/tex] = [tex]\frac{15.0}{17.031}[/tex] moles of [tex]NH_{3}[/tex] = 0.8807 moles of [tex]NH_{3}[/tex]

      250 g of [tex]H_{2}O[/tex] = [tex]\frac{250}{18.015}[/tex] moles of [tex]H_{2}O[/tex] = 13.88 moles of [tex]H_{2}O[/tex]

So, Mole fraction of [tex]NH_{3}[/tex] in the solution = (no.of moles of [tex]NH_{3}[/tex] )/(total no. of moles) = [tex]\frac{0.8807}{0.8807+13.88}[/tex] = 0.0597

Hence, mole fraction of [tex]NH_{3}[/tex] in solution is 0.0597.

Otras preguntas