Answer:
46.77N/m
Explanation:
to find the spring constant you can use the following formula:
[tex]T=2\pi\sqrt{\frac{m}{k}}[/tex]
T: period of oscillation = 0.65s
m: mass of the object = 0.50kg
By doing k the subject of the formula and replacing you obtain:
[tex]k=4\pi^2\frac{m}{T^2}=4\pi^2\frac{0.50kg}{(0.65s)^2}=46.72\frac{N}{m}[/tex]
hence, the spring constant is 46.77N/m
Answer:
46.67 N/m.
Explanation:
Using,
T = 2π[√(m/k)].............. Equation 1
Where T = period of the oscillation, m = mass attached to the end of the spring, k = spring constant of the spring.
make k the subject of the equation.
k = (4π²)m/T²................ Equation 2
Given: T = 0.65 s, m = 0.5 kg, π = 3.14
Substitute into equation 2
k = 0.5(4×3.14²)/0.65²
k = 46.67 N/m
Therefore the force constant of the spring = 46.67 N/m
