Answer:
0.9209
Explanation:
For a normally distributed random variable, the only way to find areas is using the z score. The z score is given by the equation:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
Where μ is the mean, σ is the standard deviation and x is the raw score to be measured.
The area under the standard normal curve that lies between the interval z=-2.73 and z=-1.39
From the z table, Area between -2.73 and -1.39 = P(z < -1.39) - P(z < -2.73) = 0.0823 - 0.0032 = 0.0791
Since the Area between -2.73 and -1.39 is 0.0791, the are outside the interval = 1 - 0.0791 = 0.9209
Based on the information given, it should be noted that the area under the standard normal curve that lies outside the interval given will be 0.9209.
It should be noted that a z-score is simply the measure of position that shows the number of standard deviations a data value lies from the mean. For a normally distributed random variable, the area can be found by using the z score.
The formula for calculating a z-score is given as:
z = (x-μ)/σ,
where
x = raw score,
μ = population mean,
σ = population standard deviation.
In this case, the area under the standard normal curve that lies between the interval given by looking at the z table is 0.0791.
Now, to calculate the area under the standard normal curve that lies outside the interval will be:
= 1 - 0.0791
= 0.9209
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