Answer:
840
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo.
My answer:
In the menu, there are 6 main ingredients and we take 2 at the same time, so the possible outcomes is:
[tex]C^{6} _{2}[/tex] = [tex]\frac{6!}{(6-2)!*2!}[/tex] = 15
In the menu, there are 8 toppings and we take 3 at the same time, so the possible outcomes is:
[tex]C^{8} _{3}[/tex] = [tex]\frac{8!}{(8-3)!*3!}[/tex] = 56
=> the total number of combinations :
=[tex]C^{6} _{2}[/tex]*[tex]C^{8} _{3}[/tex]
=15 * 56 = 840
