Answer:
Area of a 30-inch circular mirror is greater than area of a 18-inch circular mirror by 452.16 square inches.
Step-by-step explanation:
We are given the following in the question:
Mirror 1:
[tex]d_1 = 30\text{ inches}\\\\\Rightaroow r_1 = \dfrac{30}{2}=15\text{ inches}[/tex]
Area of mirror 1 = Area of circle
[tex]A_1 = \pi r_1^2[/tex]
Putting values, we get,
[tex]A_1 = 3.14\times (15)^2=706.5\text{ square inches}[/tex]
Mirror 2:
[tex]d_1 = 18\text{ inches}\\\\\Rightaroow r = \dfrac{18}{2}=9\text{ inches}[/tex]
Area of mirror 1 = Area of circle
[tex]A_2 = \pi r_2^2[/tex]
Putting values, we get,
[tex]A_2 = 3.14\times (9)^2=254.34\text{ square inches}[/tex]
Difference between area =
[tex]=A_1-A_2\\=706.5-254.34\\=452.16\text{ square inches}[/tex]
Thus, area of a 30-inch circular mirror is greater than area of a 18-inch circular mirror by 452.16 square inches.
