In one of your trials you placed 5.5 grams of salt in 10 ml of water. Use this information to answer the following questions.
a. What is the w/w%?
b. What is the w/v%
c. How many moles of NH4Cl are used? Remember, moles = mass/molar mass
d. Using the moles from 4c find the molarity.

Respuesta :

Answer:I think it is C not positive though

Explanation:

In one of your trials you placed 5.5 grams of salt in 10 ml of water. (a) The w/w % is 35.48% (b) The w/v % is 55 % (c) The moles of NH₄Cl is 0.1  mol (d) The molarity of solution is 10 M.

How to calculate the percentage concentration (w/w) ?

Concentration % (w/w) = [tex]\frac{\text{Weight of solute}}{\text{Weight of solution}} \times 100[/tex]

Weight of solution = Solute + Solvent

                              = 5.5 g + 10g    [ 1 ml water = 1 g water]

                              = 15.5

Concentration % (w/w) = [tex]\frac{\text{Weight of solute}}{\text{Weight of solution}} \times 100[/tex]

                                     = [tex]\frac{5.5}{15.5} \times 100[/tex]

                                     = 0.3548 × 100

                                     = 35.48 %

How to calculate the percentage concentration (w/v) ?

Concentration %(w/v) = [tex]\frac{\text{Mass of solute (in g)}}{\text{Volume of solution (in ml)}} \times 100[/tex]

                                    = [tex]\frac{5.5}{10} \times 100[/tex]

                                    = 55%

How to find the number of mole ?

To calculate the number of moles of a substance we have to divide the given mass/weight of the substance by the molar mass of the substance.

Moles = [tex]\frac{\text{Given Mass}}{\text{Molar mass }}[/tex]

          = [tex]\frac{5.5}{53.5}[/tex]

          = 0.1 mol

What is Molarity ?

Molarity (M) is defined as the number of solute dissolved in per liter of solution.

Molarity (M) = [tex]\frac{\text{Number of moles of solute}}{\text{Volume of solution (in liters)}}[/tex]

Convert ml into l

1 ml = 0.001 liter

10 ml = 10 × 0.001

         = 0.01 liter

Now put the value in above formula we get

Molarity (M) = [tex]\frac{\text{Number of moles of solute}}{\text{Volume of solution (in liters)}}[/tex]

                    = [tex]\frac{0.1}{0.01}[/tex]

                    = 10 M

Thus from the above conclusion we can say that In one of your trials you placed 5.5 grams of salt in 10 ml of water. (a) The w/w % is 35.48% (b) The w/v % is 55 % (c) The moles of NH₄Cl is 0.1  mol (d) The molarity of solution is 10 M.

Learn more about the Molarity here: https://brainly.com/question/26873446
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