Respuesta :
Answer: The number of moles of [tex]CO_2[/tex] produced are, 0.287 moles.
Explanation : Given,
Mass of [tex]O_2[/tex] = 14.9 g
Molar mass of [tex]O_2[/tex] = 32 g/mol
First we have to calculate the moles of [tex]O_2[/tex]
[tex]\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}[/tex]
[tex]\text{Moles of }O_2=\frac{14.9g}{32g/mol}=0.466mol[/tex]
Now we have to calculate the moles of [tex]CO_2[/tex]
The balanced chemical equation is:
[tex]2C_4H_{10}+13O_2\rightarrow 10H_2O+8CO_2[/tex]
From the reaction, we conclude that
As, 13 mole of [tex]O_2[/tex] react to give 8 moles of [tex]CO_2[/tex]
So, 0.466 mole of [tex]O_2[/tex] react to give [tex]\frac{8}{13}\times 0.466=0.287[/tex] mole of [tex]CO_2[/tex]
Therefore, the number of moles of [tex]CO_2[/tex] produced are, 0.287 moles.
