At a canning facility, a technician is testing a machine that is supposed to deliver 250 milliliters of product. The technician tests 44 samples and determines the volume of each sample. The 44 samples have a mean volume of 251.6 mL. The machine is out of calibration when the average volume it dispenses differs significantly from 250 mL.


The technician wants to perform a hypothesis test to determine whether the machine is out of calibration. Assume standard deviation = 5.4 is known. Compute the value of the test statistic.


Potential answers are:


4.57


0.30


13.04


0.24


1.97

Respuesta :

Answer:

1.97

Step-by-step explanation:

The null hypothesis is:

[tex]H_{0} = 250[/tex]

The alternate hypotesis is:

[tex]H_{1} \neq 250[/tex]

Our test statistic is:

[tex]t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the hypothesis tested(null hypothesis), [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

In this problem, we have that:

[tex]X = 251.6, \mu = 250, \sigma = 5.4, n = 44[/tex]

So

[tex]t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]t = \frac{251.6 - 250}{\frac{5.4}{\sqrt{44}}}[/tex]

[tex]t = 1.97[/tex]