The equation in slope-intercept from is y = [tex]\frac{9}{8}x - \frac{3}{8}[/tex].
Step-by-step explanation:
Given,
x = 8t+3
y= 9t+3
First, convert both the equations in terms of t for comparison.
x = 8t + 3
x - 3 = 8t
t = [tex]\frac{x-3}{8}[/tex]
Similarly,
y = 9t + 3
y - 3 = 9t
t = [tex]\frac{y-3}{9}[/tex]
Now, comparing both equations
[tex]\frac{x-3}{8}[/tex] = [tex]\frac{y-3}{9}[/tex]
9x -27 = 8y -24
9x - 3 = 8y
or
y = [tex]\frac{9}{8}x - \frac{3}{8}[/tex]
Hence, the equation in slope-intercept from is y = [tex]\frac{9}{8}x - \frac{3}{8}[/tex].