Complete the proof of the Law of Sines/Cosines.

Given triangle ABC with altitude segment BD labeled x. Angles ADB and CDB are right angles by _____1._____, making triangle ABD and triangle BCD right triangles. Using the trigonometric ratios sine of A equals x over c and sine of C equals x over a. Multiplying to isolate x in both equations gives x = _____2._____ and x = a ⋅ sinC. We also know that x = x by the reflexive property. By the substitution property, _____3._____. Dividing each side of the equation by ac gives: sine of A over a equals sine of C over c.


1. definition of altitude

2. c ⋅ sinA

3. c ⋅ sinA = a ⋅ sinC

1. definition of right triangles

2. c ⋅ sinB

3. c ⋅ sinB = a ⋅ sinC

1. definition of right triangles

2. a ⋅ sinA

3. a ⋅ sinA = c ⋅ sinC

1. definition of altitude

2. c ⋅ sinA

3. a ⋅ sinA = c ⋅ sinC

Respuesta :

Answer:

(A)

  1. Definition of altitude
  2. c⋅sinA
  3. [tex]c\cdot sinA=a\cdot sinC[/tex].

Step-by-step explanation:

Law of Sines/Cosines.

  • Given triangle ABC with altitude segment BD labeled x. Angles ADB and CDB are right angles by the (1) definition of altitude making triangle ABD and triangle BCD right triangles.
  • Using the trigonometric ratios [tex]sin A=\dfrac{x}{c}[/tex] and [tex]sin C=\dfrac{x}{a}[/tex].
  • Multiplying to isolate x in both equations gives (2)[tex]x=c\cdot sinA[/tex] and [tex]x=a\cdot sinC.[/tex]
  • We also know that x = x by the reflexive property.
  • By the substitution property,(3)[tex]c\cdot sinA=a\cdot sinC[/tex].
  • Dividing each side of the equation by ac gives:

[tex]\frac{c\cdot sinA}{ac} =\frac{a\cdot sinC}{ac} \\\frac{ sinA}{a} =\frac{sinC}{c}[/tex]

Answer: answer A

Step-by-step explanation:

1. Definition of altitude

2. c • sinA

3. c • SinA= a • sinC