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Consider the reaction.

2 upper H upper F (g) double-headed arrow upper H subscript 2 (g) plus upper F subscript 2 (g).

At equilibrium at 600 K, the concentrations are as follows.

[HF] = 5.82 x 10-2 M
[H2] = 8.4 x 10-3 M
[F2] = 8.4 x 10-3 M

What is the value of Keq for the reaction expressed in scientific notation?

Respuesta :

Answer:

2.1 x 10^-2

Explanation:

Divide 8.4 x 10^-3 x 8.4 x 10^-3 by 5.82 x 10^-2 and you end up with 2.1 x 10^-2

12.12 x 10^{-4} is the value of Keq for the reaction.

What is chemical equilibrium?

Chemical equilibrium is the condition where no net change in the amounts of reactants and products occurs.

[tex]Keq =\frac{[H_2] [F_2] }{[HF]^2}[/tex]

[tex]Keq =\frac{[8.4 x 10^{-3}] [8.4 x 10^{-3}] }{5.82 x 10^{-2}}[/tex]

12.12 x [tex]10^{-4}[/tex]

Hence, 12.12 x [tex]10^{-4}[/tex] is the value of Keq for the reaction.

Learn more about chemical equilibrium here:

brainly.com/question/4289021

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