Please help me!!!!! How do you get 67.3 and 112.7 from .9228
I attached the problem with the answer but not all the work.
In will make the first answer the brainlyest

Please help me How do you get 673 and 1127 from 9228 I attached the problem with the answer but not all the work In will make the first answer the brainlyest class=

Respuesta :

Answer and Step-by-step explanation:

You are correct in that we need to use the Law of Sines: [tex]\frac{c}{sinC} =\frac{b}{sinB}=\frac{a}{sinA}[/tex].

Here, when we use the Law of Sines, we have: [tex]\frac{28}{sin(63)}=\frac{29}{sinB}[/tex].

Cross multiply:

(sinB) * 28 = (sin63) * 29

28sinB ≈ 25.839

sinB ≈ 0.9228

Now, in order to solve for B, we need to use inverse sin ([tex]sin^{-1}[/tex]):

[tex]sin^{-1}(sinB)=sin^{-1}(0.9228)[/tex]

The sines on the left cancel out, and we're left with:

B ≈ 67.3 degrees

Now, one thing to keep in mind when doing Law of Sines is that there is potentially more than one answer possible for the degree measure. The other degree measure can be found by subtracting this one from 180:

180 - 67.3 = 112.7 degrees.

Hope this helps!

Answer:

67.3° , 112.7°

Step-by-step explanation:

sinx = 0.9228

Take inverse of sin, you get:

x = 67.3389176683

Since sin is positive in first two quadrants, second angle is:

180 - 67.3389176683

= 112.6610823317