Answer : The number of moles of [tex]NaCl[/tex] formed are, 0.69 moles.
Explanation : Given,
Moles of [tex]CaCl_2[/tex] = 0.345 mol
Now we have to calculate the moles of [tex]NaCl[/tex]
The balanced chemical equation is:
[tex]1Na_2CO_2(aq)+1CaCl_2(aq)\rightarrow 1CaCO_3(s)+2NaCl(aq)[/tex]
From the balanced reaction, we conclude that
As, 1 mole of [tex]CaCl_2[/tex] react to give 2 moles of [tex]NaCl[/tex]
So, 0.345 mole of [tex]CaCl_2[/tex] react to give [tex]2\times 0.345=0.69[/tex] mole of [tex]NaCl[/tex]
Therefore, the number of moles of [tex]NaCl[/tex] formed are, 0.69 moles.
