Respuesta :
Answer:
0.3694
Step-by-step explanation:
In this question, we are asked to calculate the probability that a golfer scored at least 74 if she played on a particular day.
Given that ,
mean = µ = 73
standard deviation = σ = 3
P(x > 74) = 1 - P(x<74 )
= 1 - P[(x -µ) / σ < (74 -73) /3 ]
= 1 - P(z <0.3333 )
Using z table
= 1 - 0.6305
= 0.3694
probability= 0.3694
The probability that her score is at least 74 should be 0.3694 at the time when the mean and standard deviation is 73 and 4.
Calculation of the probability:
Here the mean should be dealt with the average of the numbers.
Since there is a mean of 73 and a standard deviation of 3.
So,
P(x > 74) = 1 - P(x<74 )
So,
[tex]= 1 - P[(x -\mu ) / \sigma < (74 -73) /3 ][/tex]
= 1 - P(z <0.3333 )
Now here we use z table
= 1 - 0.6305
= 0.3694
Therefore, we can conclude that the probability that her score is at least 74 is 0.3694.
Learn more about probability here: https://brainly.com/question/16096170
