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An athlete throws a ball straight upward with an initial speed of 12 meters per second. The ball

reaches a maximum height and then falls back down toward the athlete. What are the

magnitudes of the velocity and acceleration of the ball at its maximum height?

O A. velocity = 0 m/s; acceleration = 0 m/s

B. velocity = 0 m/s, acceleration = 9.8 m/s

O C. velocity = 12 m/s; acceleration = 0 m/s

OD. velocity = 12 m/s; acceleration = 9.8 m/s

Respuesta :

mavila18

Answer:

B. velocity = 0 m/s, acceleration = 9.8 m/s

Explanation:

When the ball reaches the maximum height all energy is potential energy. Because of that, the kinetic energy of the ball is zero and the velocity is also zero. The acceleration of the ball is in all trajectory the gravitational constant, because the gravitational force always acts over the ball.

Hence, the velocity is 0m/s and the acceleration is 9.8m/s^2

B. velocity = 0 m/s, acceleration = 9.8 m/s

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