Answer:
Step-by-step explanation:
Given that three fair coins are flipped.
Sample space for the given event is
[tex]S={\{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}\}[/tex]
Let A be the events of getting atleast 2 Heads and is given by
A = {HHH, HHT, HTH, THH}
Probability of Getting atleast 2 Heads in 3 Coin Tosses is
[tex]P(A)=\frac{n(A)}{n(S)}[/tex]
[tex]P(A)=\frac{4}{8}[/tex]
[tex]=0.5[/tex]