The area of the irregular shape is 38 cm^3.
The area of the triangle is half times of base and height.
[tex]\rm Area \ of \triangle=\dfrac{1}{2} \times Base \times height[/tex]
A tile installer plots an irregular shape on grid paper.
Each square on the grid represents 1 square centimeter.
The area of the triangle is;
[tex]\rm Area \ of \triangle=\dfrac{1}{2} \times Base \times height\\\\Area \ of \triangle=\dfrac{1}{2} \times4 \times 4\\\\Area \ of \triangle=8[/tex]
The area of the rectangle is;
[tex]\rm Area \ of \ recatngle =length \times width\\\\ Area \ of \ recatngle =3 \times 5\\\\ Area \ of \ recatngle =15[/tex]
The area of the parallelogram is;
[tex]\rm Area \ of \ a \ parallelogram = base \times height\\\\ Area \ of \ a \ parallelogram =5\times 3\\\\ Area \ of \ a \ parallelogram =15[/tex]
The area of the irregular shape is;
= 8 + 15 + 15=38
Hence, the area of the irregular shape is 38 cm^3.
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