Answer:
Explanation:
Given that,
Electric Field is
E = 650 N/C
The potential at x1 = 3 is
V1 = 1700V
What is the potential at x2 = 1
V2 =?
Electric potential is given as
V = Ed
Then,
E = V/d
Therefore, the electric field is gradient of the potential and the position.
So,
E = —∆V / ∆x
E = — (V2 — V1) / (x2 — x1)
E = —(V2—1700) / (1—3)
650 = — ( V2—1700) / -2
650 × -2 = —V2 + 1700
-1300 = -V2 + 1700
V2 = 1700+1300
V2 = 3000 V
