The California mussel (Mytilus californianus) attaches itself to a rock or other solid surface with a bundle of filaments known as the byssus. Imagine that 15.0 J of work is done to stretch the distal end of the byssus. It releases 10.8 J of thermal energy as it relaxes. What is the resilience of the distal end of the byssus

Respuesta :

Answer:

0.28

Explanation:

Thermal energy is 10.8 J

Work done is 15 J

Let r be the resilience of the distal end of the byssus

We have the relation

[tex]10.8=15-r15[/tex]

[tex]\Rightarrow 10.8-15=-r15[/tex]

[tex]\Rightarrow 4.2=r15[/tex]

[tex]\Rightarrow r=\dfrac{4.2}{15}[/tex]

[tex]\Rightarrow r=0.28[/tex]

So, the resilience of the distal end of the byssus is 0.28

The resilience of the distal end of the byssus is 0.28.

The given parameters;

  • work done in stretching the distal, W = 15 J
  • energy released, E = 10.8 J

The resilience of the distal end of the byssus is calculated by applying the following equations as shown below;

W = E - Er

10.8 = 15 - 15r

15r = 15 - 10.8

15r = 4.2

[tex]r = \frac{4.2}{15}\\\\r = 0.28[/tex]

Thus, the resilience of the distal end of the byssus is 0.28.

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