Respuesta :
Answer:
0.28
Explanation:
Thermal energy is 10.8 J
Work done is 15 J
Let r be the resilience of the distal end of the byssus
We have the relation
[tex]10.8=15-r15[/tex]
[tex]\Rightarrow 10.8-15=-r15[/tex]
[tex]\Rightarrow 4.2=r15[/tex]
[tex]\Rightarrow r=\dfrac{4.2}{15}[/tex]
[tex]\Rightarrow r=0.28[/tex]
So, the resilience of the distal end of the byssus is 0.28
The resilience of the distal end of the byssus is 0.28.
The given parameters;
- work done in stretching the distal, W = 15 J
- energy released, E = 10.8 J
The resilience of the distal end of the byssus is calculated by applying the following equations as shown below;
W = E - Er
10.8 = 15 - 15r
15r = 15 - 10.8
15r = 4.2
[tex]r = \frac{4.2}{15}\\\\r = 0.28[/tex]
Thus, the resilience of the distal end of the byssus is 0.28.
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