Answer:
Final Pressure of the gas is 1.675 atm
Explanation:
Given: Initial Volume: V₁ = 2.5 L, Initial Pressure: P₁ = 0.9 atm, Initial Temperature: T₁ = 22 °C = 22 + 273 = 295 K
Final Volume: V₂ = 1.5 L, Final Temperature: T₂ = 56.5 °C = 56.5 + 273 = 329.5 K, (∵ 0°C = 273 K)
Final Pressure: P₂ = ?
According to the Combined Gas Law:
[tex]\frac{P_{1}V_{1}}{T_{1}}= \frac{P_{2}V_{2}}{T_{2}}[/tex]
[tex]\Rightarrow P_{2} = \frac{P_{1}V_{1}T_{2}}{T_{1}V_{2}}[/tex]
[tex]\Rightarrow P_{2} = \frac{0.9 \: atm\times 2.5 \: L\times 329.5 \: K}{295 \: K\times 1.5 \: L}= 1.675 \: atm[/tex]
Therefore, the Final Pressure of the given gas: P₂ = 1.675 atm
