Suppose that in solving an equation over the interval [0 comma 360 degrees )[0,360°)​, you reach the step sine theta equals negative one halfsinθ=− 1 2. Why is minus−30degrees° not a correct​ answer?

Respuesta :

Answer:

The sign of the trigonometric ratio only aid you to determine the quadrant in which the ratio lies.

Step-by-step explanation:

Given [TeX]sin \theta=- \frac{1}{2}[/TeX]

[TeX]\theta \neq -30[/TeX]

The trigonometric ratio sine is negative in the 3rd and 4th Quadrant. Therefore if [TeX]sin \theta=- \frac{1}{2}[/TeX], the value(s) of [TeX]\theta [/TeX] in the interval [0,360°) will be in the 3rd and 4th Quadrant.

To obtain the value of [TeX]\theta [/TeX] in these quadrants:

Solve for [TeX]sin \theta=\frac{1}{2}\\sin^{-1}\frac{1}{2}=30^{0}[/TeX]

In the 3rd Quadrant, [TeX]\theta =180+30=210^{0} [/TeX]

In the 4th Quadrant, [TeX]\theta =360-30=330^{0} [/TeX] .

The sign of the trigonometric ratio only aid you to determine the quadrant in which the ratio lies.