Answer:
5
Step-by-step explanation:
We are being asked in how many ways an enumerated ball can be removed without any type of replacement, therefore it would be a combination without repetition:
nCr = n! / r! * (n-r)!
n, total number of balls, 5
r, specific number of balls, 1
5C1 = 5! / (1! * 4!) = 5
Therefore there are 5 ways to do the above.
