Answer:
The energy required is [tex]E= 3.375*10^6J[/tex]
Explanation:
From the question we are told that
The charge is [tex]q_1 = 3.0 \mu C = 3.0*10^{-6}C[/tex]
The radius is [tex]r = 20cm = \frac{20}{100} = 0.2m[/tex]
The second charge is [tex]q_2 = 25 \mu C = 25*10^{-6}C[/tex]
Generally the energy required is mathematically represented as
[tex]E = \frac{k q_1 q_2 }{R}[/tex]
Where k is the coulomb constant with a value of [tex]k = 9*10^9kg m^3 s^{-4} A^{-2}[/tex]
Substituting values we have
[tex]E = \frac{9*10^9 * 3*10^{-3} * 25 *10^{-6}}{0.2}[/tex]
[tex]E= 3.375*10^6J[/tex]
