HELP PLEASE PLEASE :’(

The path of a shotput thrown is represented by the following parametric equations. Distance is measured in feet and time in seconds. Rewrite the parametric equations by eliminating the time parameter.
x(t)=23t
y(t)=5+19.3t-16t^2

a. y=5+444x-10,210x^2, x>or equal to 0
b. y=5+0.84x-0.70x^2, x>or equal to 0
c. y=5+444x-16x^2, x>or equal to 0
d. y=5+0.84x-0.03x^2, x>or equal to 0

Water is dripping out of a gutter onto a splash guard that follows the path represented by the parametric equations. Rewrite the parametric equations by eliminating the parameter.
x(t)=e^t
y(t)=2e^-t

a. y= 2/x, x>or equal to 0
b. y= 2/x, x>0
c. y= 2/(x^2), x>or equal to 0
d. y= 2/(x^2), x>0

Thanks!!!!!!

For the first parametric functions the cartisian function is y = 5+ 0.84x - 0.7x², and for the second parametric function the cartisian function is y = 2/x where x>0

What are parametric equations?

A parametric equation in mathematics specifies a set of numbers as functions of one or more independent variables known as parameters.

For the first parametric functions:

[tex]\rm x(t)=23t \\\\y(t)=5+19.3t-16t^2[/tex]

[tex]\rm t = \dfrac{x}{23}[/tex]

Put this value in the y(t)

[tex]\rm y=5+19.3(\dfrac{x}{23})-16(\dfrac{x}{23})^2[/tex]

y = 5+ 0.84x - 0.7x²

For the second parametric functions

[tex]\rm x(t)=e^t .....(1)\\\\y(t)=2e^-^t[/tex]

Taking ln in equation (1)

lnx = t

Put this value in equation (2)

[tex]\rm y=2e^{-lnx}[/tex]

y = 2/x, x>0

Thus, for the first parametric functions the cartisian function is y = 5+ 0.84x - 0.7x², and for the second parametric function the cartisian function is y = 2/x where x>0

Learn more about the parametric function here:

https://brainly.com/question/10271163

#SPJ2