0.185 M is the molar concentration of sodium nitrate should appear on the label.
Explanation:
Data given:
mass of NaNO3 = 3.166 grams
atomic mass of NaNO3 = 84.99 grams/mole
volume of the solution = 200 ml or 0.2 litres
molar concentration of sodium nitrate solution = ?
first number of moles of sodium nitrate is calculated as:
number of moles = [tex]\frac{mass}{atomic mass of 1 mole}[/tex]
number of moles = [tex]\frac{3.166}{85}[/tex]
number of moles = 0.037 moles
molarity = [tex]\frac{number of moles}{\volume in litres}[/tex]
putting the values in the equation:
molarity = [tex]\frac{0.037}{0.2}[/tex]
molarity = 0.185
Molar concentration of the sodium nitrate solution made with 3.166 grams of NaNO3 in 200 ml solution is 0.185 M
