Respuesta :

xero099

Answer:

[tex](x-9.291)\cdot (x + 1.292)[/tex]

Step-by-step explanation:

The factors of the given polynomial ([tex]x^{2}-8\cdot x - 12[/tex]) are derived from the General Formula for Second-Order Polynomials:

[tex]x = \frac{8 \pm \sqrt{64 - 4\cdot (1)\cdot (-12)}}{2\cdot (1)}[/tex]

[tex]x_{1} \approx 9.291[/tex] and [tex]x_{2} \approx -1.292[/tex]

The factors of the polynomial are:

[tex](x-9.291)\cdot (x + 1.292)[/tex]

ibnahmadbello

Answer:

The answer is prime.

Step-by-step explanation:

x2 – 8x – 12

We need two numbers which are factors of 12 such that their product is -12 and their sum is -8. The factors are 1, 2, 3, 4 and 6 but no two numbers satisfy the requirements of summing up to -8 and product of -12.

Therefore the equation is a prime as it has no factor

We can also check if the equation has a factor using the formula for general quadratic equation of ax² + bx + c = 0, the formula is;

(b² - 4ac)

If the answer is a perfect square only then we can factorize the equation.

In the given equation x² - 8x - 12

b = -8 and c = -12

b²- 4ac = (-8)² - 4(1)(-12) = 64 + 48 = 112

Since 112 is not a perfect square number, we can say there is no factors for the given equation.

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