Answer : The molality of sodium chloride is, 1.79 m
Explanation :
To calculate the molality of solution, we use the equation:
[tex]\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}[/tex]
Where,
[tex]m_{solute}[/tex] = Given mass of solute (sodium chloride) = 49 g
[tex]M_{solute}[/tex] = Molar mass of solute (sodium chloride) = 58.5 g/mol
[tex]W_{solvent}[/tex] = Mass of solvent (water) = 469 g
Now put all the given values in above equation, we get:
[tex]\text{Molality of }NaCl=\frac{49g\times 1000}{58.5g/mol\times 469kg}\\\\\text{Molality of }NaCl=1.79mol/kg=1.79m[/tex]
Hence, the molality of sodium chloride is, 1.79 m
