Answer : The temperature of neon gas will be, 221.0 K
Explanation :
To calculate the temperature of neon gas we are using ideal gas equation.
[tex]PV=nRT\\\\PV=\frac{w}{M}RT[/tex]
where,
P = pressure of neon gas = 96.7 kPa = 0.955 atm
Conversion used : (1 atm = 101.3 kPa)
V = volume of neon gas = 9.50 L
T = temperature of neon gas = ?
R = gas constant = 0.0821 L.atm/mole.K
w = mass of neon gas = 10.00 g
M = molar mass of neon gas = 20 g/mole
Now put all the given values in the ideal gas equation, we get:
[tex](0.955atm)\times (9.50L)=\frac{10.00g}{20g/mole}\times (0.0821L.atm/mole.K)\times T[/tex]
[tex]T=221.0K[/tex]
Therefore, the temperature of neon gas will be, 221.0 K
