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30.00 mL of a H2SO4 solution with an unknown concentration was titrated to a phenolphthalein endpoint with 37.85 mL of a 0.1361 M NaOH solution. What is the concentration of the H2SO4 solution

Respuesta :

Answer:

The concentration of the H2SO4 solution is 0.0858 M

Explanation:

Step 1: Data given

Volume of H2SO4 = 30.00 mL = 0.030 L

Volume of NaOH= 37.85 mL = 0.03785 L

Concentration of NaOH= 0.1361 M

Step 2: The balanced equation

H2SO4 + 2NaOH → Na2SO4 + 2H2O

Step 3: Calculate the concentration of the H2SO4 solution

b*Ca*Va = a*Cb*Vb

⇒with b = the coefficient of NaOH = 2

⇒with Ca = the concentration of H2SO4 = TO BE DETERMINED

⇒with Va = the volume of H2SO4= 30.0 mL = 0.030 L

⇒with a = the coefficient of H2SO4 = 1

⇒with Cb = the concentration of NaOH = 0.1361 M

⇒with Vb = the volume of NaOH = 37.85 mL = 0.03785 L

2*Ca*0.030 = 1* 0.1361 * 0.03785

0.060 * Ca = 0.00515

Ca = 0.0858 M

The concentration of the H2SO4 solution is 0.0858 M

The concentration of the H2SO4 solution should be 0.0858 M.

Calculation of the concentration:

Since

Volume of H2SO4 = 30.00 mL = 0.030 L

Volume of NaOH= 37.85 mL = 0.03785 L

Concentration of NaOH= 0.1361 M

Now

The balanced equation is

H2SO4 + 2NaOH → Na2SO4 + 2H2O

Now the concentration of the H2SO4 solution is

b*Ca*Va = a*Cb*Vb

here,  b = the coefficient of NaOH = 2

Ca = ?

Va = the volume of H2SO4= 30.0 mL = 0.030 L

a = the coefficient of H2SO4 = 1

Cb = the concentration of NaOH = 0.1361 M

Vb = the volume of NaOH = 37.85 mL = 0.03785 L

Now

2*Ca*0.030 = 1* 0.1361 * 0.03785

0.060 * Ca = 0.00515

Ca = 0.0858 M

hence, The concentration of the H2SO4 solution is 0.0858 M.

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