Respuesta :
Answer:
1. [tex]Q = 5.56 * 10^{-3} C[/tex]
2.[tex]Q = 2.97 * 10^{-12} C[/tex]
Explanation:
1. Electrostatic force is given as:
[tex]F = \frac{kqQ}{r^2}[/tex]
where k = Coulombs constant
q = charge of first charge
Q = charge of the second charge
r = distance between them
From the question:
F = 100 N
q = [tex]2 * 10^{-10} C[/tex]
r = 0.01 m
We need to find Q.
From the formula of force, we have that Q is:
[tex]Q = \frac{Fr^2}{kq}[/tex]
[tex]Q = \frac{100 * 0.01^2}{8.99 * 10^9 *2 * 10^{-10}} \\\\\\Q = \frac{0.01}{1.798}\\ \\\\Q = 0.00556 C = 5.56 * 10^{-3} C[/tex]
This is the charge, Q, of the second charge.
2. From the question:
F = 2 N
q = [tex]3 * 10^{-6} C[/tex]
r = [tex]2 *10^{-4} m[/tex]
We need to find Q.
Using the same formula for Q as in 1. above, we have that:
[tex]Q = \frac{2 * (2 *10^{-4})^2}{8.99 * 10^9 *3 * 10^{-6}} \\\\\\Q = \frac{8 * 10^{-8}}{26970}\\ \\\\Q = 2.97 * 10^{-12} C[/tex]
This is the charge, Q, of the second charge.
Answer:
(1) [tex]4.4835*10^{17}C[/tex]
(2) [tex]2.9748*10^{-12}C[/tex]
Explanation:
Force Between two charges is give by.
[tex]F=k\frac{Q_1 *Q_2}{r^2}[/tex] , here k is called coulomb constant and has value = [tex]8.967*10^9Nm^2/C[/tex].
(1) case, F =100N, r = 0.1m and [tex]Q_1[/tex]=[tex]2*10^{-10}C[/tex] substituting these values in above equation and solving for unknown gives us.
[tex]Q_2 = 4.4835*10^{17}C[/tex].
(2) Case, F = 2N, r = [tex]2*10^{-4}m[/tex] and [tex]Q_1=3*10^{-6}C[/tex].
again by substituting these in above equation and solving for unknown gives us.
[tex]Q_2=2.9748*10^{-12}C.[/tex]
