1. If 100 mL of a gas, originally at 760 torr, is compressed to a pressure of 120 kPa

at constant temperature, what will its final volume be?

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

[tex]P\propto \frac{1}{V}[/tex]

or,

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1[/tex] = initial pressure = 760 torr

[tex]P_2[/tex] = final pressure = 120 kPa = 900 torr (1 kPa = 7.5 torr)

[tex]V_1[/tex] = initial volume = 100 mL

[tex]V_2[/tex] = final volume = ?

Now put all the given values in the above equation, we get:

[tex]760torr\times 100mL=900torr\times V_2[/tex]

[tex]V_2=84.4mL[/tex]

Therefore, the final volume will be, 84.4 mL

1. If 100 mL of a gas, originally at 760 torr, is compressed to a pressure of 120 kPa at constant temperature, what will its final volume be?

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1. If 100 mL of a gas, originally at 760 torr, is compressed to a pressure of 120 kPa

at constant temperature, what will its final volume be?