Answer:
12 degrees
Step-by-step explanation:
[tex]b^2=a^2+t^2-2atCosB\\15^2=50^2+60^2-2(50)(60)Cos B\\Cos B=\frac{15^2-(50^2+60^2)}{-2(50)(60)} \\Cos B=0.9792\\B=arc Cos 0.9792\\B=11.7^0[/tex]
Maricel's code will adjust the shot by 12 degrees to the nearest degree.