Answer:
no of revolutions = 56.62 rev
Explanation:
given data
rotates = 1560 rpm
travels distance = 18.5 meters
speed = 40.2 m/s
solution
first we convert here rev/min to rev/sec
rotates = 1560 rpm = 1560 × 0.0167 = 26.052 rev/sec
we get here no of revolutions that is
no of revolutions = spin rotate ÷ time ..........1
here time = distance ÷ speed
time = 18.5 ÷ 40.2
time = 0.4601 s
put value in equation 1 we get
no of revolutions = [tex]\frac{26.052}{0.4601}[/tex]
no of revolutions = 56.62 rev
